BriTheMathGuy
BriTheMathGuy
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So Why Do We Treat It That Way?
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Переглядів: 127 410

Відео

My Most Controversial Integral
Переглядів 53 тис.Місяць тому
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . You’ll also get 20% off an annual premium subscription. 🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Website www.brithemathguy.com 🙏Support me by becoming a channel member! ua-...
Theorems That Disappointed Mathematicians
Переглядів 79 тис.2 місяці тому
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . You’ll also get 20% off an annual premium subscription. 🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Website www.brithemathguy.com 🙏Support me by becoming a channel member! ua-...
What Actually Is A Number?
Переглядів 24 тис.2 місяці тому
Get a 7-day free trial and 25% off Blinkist Annual Premium by clicking: bit.ly/BriTheMathGuyMar24 🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Website www.brithemathguy.com 🙏Support me by becoming a channel member! ua-cam.com/channels/hVUSXFzV8QCOKNWGfE56YQ.htmljoin #math #brit...
New Math Just Dropped
Переглядів 37 тис.3 місяці тому
Get a 7-day free trial and 25% off Blinkist Annual Premium by clicking: bit.ly/BriTheMathGuyMar24 🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Website www.brithemathguy.com 🙏Support me by becoming a channel member! ua-cam.com/channels/hVUSXFzV8QCOKNWGfE56YQ.htmljoin #math #brit...
Solve This & Feel Like A Genius
Переглядів 176 тис.3 місяці тому
🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Website www.brithemathguy.com 🙏Support me by becoming a channel member! ua-cam.com/channels/hVUSXFzV8QCOKNWGfE56YQ.htmljoin #math #brithemathguy #algebra This video was partially created using Manim. To learn more about animating wit...
You Didn't Learn This In School
Переглядів 79 тис.3 місяці тому
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . The first 200 of you will get 20% off Brilliant’s annual premium subscription. We're looking for integer solutions in this one! 🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Web...
The Most Beautiful Proof
Переглядів 168 тис.4 місяці тому
🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Website www.brithemathguy.com 🙏Support me by becoming a channel member! ua-cam.com/channels/hVUSXFzV8QCOKNWGfE56YQ.htmljoin Are you fascinated by the enigmatic mathematical constant e? Ever wondered why it can't be written as a simpl...
Actual Proof 1+1=2
Переглядів 58 тис.4 місяці тому
🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C This video presents a clear and concise proof of why 1 1 equals 2, a fundamental concept in mathematics. It breaks down the logic and reasoning behind this basic equation, making it understandable for anyone interested in math. 🛜 Connect with me on my Websi...
This Video Will Improve Your Skills
Переглядів 21 тис.4 місяці тому
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . The first 200 of you will get 20% off Brilliant’s annual premium subscription. 🎓Become a Math Master With My Intro To Proofs Course! www.udemy.com/course/prove-it-like-a-mathematician/?referralCode=D4A14680C629BCC9D84C 🛜 Connect with me on my Website www.brithemathguy.com 🙏Support me by becomin...
Unlock Peak Productivity
Переглядів 7 тис.5 місяців тому
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . The first 200 of you will get 20% off Brilliant’s annual premium subscription. Dive into the world of linear programming and discover the visual approach to solving optimization problems. Our latest tutorial breaks down the concept of feasibility regions and demonstrates how to graphically repr...
Every Math Student Should Know This
Переглядів 125 тис.6 місяців тому
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . The first 200 of you will get 20% off Brilliant’s annual premium subscription. Unlock the secrets of advanced mathematics comparing 1,000^999 to 999^1,000. Ideal for math Olympiad aspirants and enthusiasts, this tutorial delves into the intriguing world of exponential comparisons. Join us as we...
Overcome Problems With One Simple Trick
Переглядів 169 тис.7 місяців тому
To try everything Brilliant has to offer-free-for a full 30 days, visit brilliant.org/BriTheMathGuy . The first 200 of you will get 20% off Brilliant’s annual premium subscription. Explore the intriguing mathematical showdown between 1.001^1000 and the number 2 ,a must-watch for Math Olympiad aspirants and math enthusiasts alike. We break down this complex comparison with engaging visuals and c...
Fear No Equation
Переглядів 120 тис.7 місяців тому
Fear No Equation
Crack The Logarithm Code: No Calculator!
Переглядів 37 тис.8 місяців тому
Crack The Logarithm Code: No Calculator!
The Secret Behind -1 Factorial
Переглядів 39 тис.9 місяців тому
The Secret Behind -1 Factorial
Exploring The Impossible: 0^i
Переглядів 70 тис.9 місяців тому
Exploring The Impossible: 0^i
Decoding The Infinite i Power Tower
Переглядів 56 тис.10 місяців тому
Decoding The Infinite i Power Tower
The Mystery Of The 0th Root
Переглядів 612 тис.10 місяців тому
The Mystery Of The 0th Root
|i Factorial| You Won't Believe The Outcome
Переглядів 342 тис.Рік тому
|i Factorial| You Won't Believe The Outcome
I'll Be Proud If You Solve This
Переглядів 27 тис.Рік тому
I'll Be Proud If You Solve This
Teachers Get Stumped
Переглядів 38 тис.Рік тому
Teachers Get Stumped
The Mystery Behind This Math Miracle
Переглядів 91 тис.Рік тому
The Mystery Behind This Math Miracle
10 Amazing Math Facts You Never Learned In School
Переглядів 125 тис.Рік тому
10 Amazing Math Facts You Never Learned In School
But What Is ∞ ^ 0
Переглядів 95 тис.Рік тому
But What Is ∞ ^ 0
You Should Learn This Trick
Переглядів 23 тис.Рік тому
You Should Learn This Trick
0 ^ ∞ , It's What You Think
Переглядів 39 тис.Рік тому
0 ^ ∞ , It's What You Think
1 ^ ∞, It's Not What You Think
Переглядів 940 тис.Рік тому
1 ^ ∞, It's Not What You Think
0 x ♾️ , It's Not What You Think
Переглядів 381 тис.Рік тому
0 x ♾️ , It's Not What You Think
You'll Enjoy This Quick Puzzle
Переглядів 19 тис.Рік тому
You'll Enjoy This Quick Puzzle

КОМЕНТАРІ

  • @RSLT
    @RSLT 7 годин тому

    Twist on Twist, actually. 9999.... is not eaxtly equal 1 .

  • @Bluebowler
    @Bluebowler 7 годин тому

    I did in mind in 4-5 sec

  • @Itamar008
    @Itamar008 9 годин тому

    I’d say 0:x=y when x=0 it would be every x

  • @coolcrafts6758
    @coolcrafts6758 9 годин тому

    Order of operations

  • @itsiwhatitsi
    @itsiwhatitsi 13 годин тому

    dy/dx is a limit that would be a 0/0 an indeterminate form

  • @johnlabonte-ch5ul
    @johnlabonte-ch5ul 18 годин тому

    I do not have to prove that ".99..." is not 1, only that the proposition that ".99..." is 1 is not valid. That the sum of infinite positive terms is a unique and precise value is not valid. That ".99..." is rational due to the definition of rational numbers is not valid. That there is no number between ".99..." and 1 is not valid. That infinite 9's or any non zero digits to the right of the radix point is an integer is not valid. That the use of the equal sign in ".99..."=1 is the same as it used in (number)=(number) is not valid. Those are some of the basics I refer to [in many previous comments and replies]. The burden of proof is necessary when you change basics.

    • @thetaomegatheta
      @thetaomegatheta 17 годин тому

      'I do not have to prove that ".99..." is not 1' You keep making that claim. Therefore, you need to prove it. Everything else you wrote is ignorable.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul 17 годин тому

      @@thetaomegatheta Thank you.

    • @thetaomegatheta
      @thetaomegatheta 17 годин тому

      Rather hilarious how you think that if you say something, it's not actually on you to back up your words.

    • @Chris-5318
      @Chris-5318 17 годин тому

      @@johnlabonte-ch5ul The only thing that you ever (and always) prove is that you are a trolling muppet.

  • @johnlabonte-ch5ul
    @johnlabonte-ch5ul 21 годину тому

    The problem in Calculus is the limit. Words like approaching do not prove something will ever equal. "As close as desired" might mean a number "next to". Then the Archimedean property takes over. It is difficult, using base 10 digits, to show that there are numbers between ".99..." and 1. Each number base has this problem. (".(b-1)(b-1)..." approaches 1). You could then find many numbers between ".99..." and 1, one in each number base higher than 10. (1/16^n, 1/20^n or 1/60^n are closer to 0 than 1/10^n) [What about "at infinity"? What is infinity? Infinity is incomplete, inconsistent and indefinite]

    • @thetaomegatheta
      @thetaomegatheta 21 годину тому

      Going to note that you are yet to back any of your claims with proof, including your claim that real numbers 1 and 9 are not integers. 'The problem in Calculus is the limit' It's not. The problem is that you think that limits of sequences and functions are magic and that the topic is too hard for you to understand, so you don't even bother looking up any definitions. 'Words like approaching do not prove something will ever equal' Yeah, they do. The expression 'f(x) approaches L as x approaches x_0' means the same thing as 'lim(f(x)) as x->x_0 = L', for example. Furthermore, for the two sequences of rational numbers a = (a_1, a_2, a_3,...) and b = (b_1, b_2, b_3,...) if lim(a_n-b_n) as n->inf = 0, then we know that lim(a) = lim(b), and that the corresponding decimals, if there are such, represent the same thing. In particular, this is true for sequences (0.9, 0.99, 0.999,...) and (1, 1, 1,...). That means that the decimals '0.999...' and '1' refer to the same number, i.e. that 0.999... = 1. Stop making wild guesses about topics that you don't understand and stop spamming everywhere. 'Then the Archimedean property takes over' The Archimedean property of the space of real numbers means that 1-0.999... = 0, i.e. that 0.999... = 1. 'It is difficult, using base 10 digits, to show that there are numbers between ".99..." and 1' It's not 'difficult'. It is literally impossible. That is true for literally every base. Notably, you provide no proof of this claim of yours. 'Each number base has this problem' It's not a problem. 'You could then find many numbers between ".99..." and 1, one in each number base higher than 10' Back this claim with proof, then, or we can confidently claim that you lied yet again. '(1/16^n, 1/20^n or 1/60^n are closer to 0 than 1/10^n)' And? 1/10^(2*n) is closer to 0 than 1/16^n, 1/20^n or 1/60^n. Now what?

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul 20 годин тому

      @@thetaomegatheta Your rebuttal [bad word choice, this is not a math debate but a UA-cam discussion] has gone to nonsense. You could have said no to each word in the comment and made as much sense. Nothing to verify here.

    • @thetaomegatheta
      @thetaomegatheta 20 годин тому

      I'm going to note right away that the only people who avoid providing proof for their claims are the people who don't understand what they are talking about and whose claims are based on nothing. 'Your rebuttal has gone to nonsense' My rebuttal is fine. 'You could have said no to each word in the comment' I could have, yes, because you provided no proof for any of your claims. And yet, I did not. I actually explained why what you were saying was incorrect and have requested you for proof of your claims.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul 20 годин тому

      @@thetaomegatheta Why do you believe 1 and 9 are not integers?

    • @thetaomegatheta
      @thetaomegatheta 20 годин тому

      I don't believe that. You do. That is your claim that stands unproven. If either of the numbers 1 and 9 is an integer, then 0.999... is obviously a rational number, which you disagree with.

  • @floridian2023
    @floridian2023 День тому

    zero

  • @PC_Simo
    @PC_Simo День тому

    0:00 Integers and whole numbers are literally the same thing: A whole unit number of something. That’s, what an integer is; and that’s, what a whole number is. The central set should have been called: ”Natural Numbers”. 😅

  • @user-ls4cw3od2u
    @user-ls4cw3od2u День тому

    No man zero mean you have none So if you divide none by none You get none You took your math with Terrance Howard Stop overthinking it If you have none You still have none 😂

  • @Arriyad1
    @Arriyad1 День тому

    You deserve to be famous as you managed to explain this in 4 minutes

  • @user-dx5wl3qb8l
    @user-dx5wl3qb8l День тому

    The 0th root of 0...

  • @ReachByteBurst
    @ReachByteBurst День тому

    Infinity is not a real number tho

  • @advocatusdiaboli7851
    @advocatusdiaboli7851 День тому

    Thank you very much. This is an eyeopener, indeed.

  • @xentarch
    @xentarch День тому

    Higher order differential terms don't exist. They can't hurt you. -Physicist

  • @shripadcn4344
    @shripadcn4344 День тому

    -1/12, theory given by Srinivasa Ramanujan

  • @Hk_498
    @Hk_498 День тому

    I’ve really wondered about this since taking my first class on differential equations several years ago, and even more since then as this idea has come up in all my physics courses, and this video finally put to rest that query that I’ve never gotten a good explanation for. Thank you so much! This has really helped me a lot.

  • @VPWedding
    @VPWedding День тому

    So if you have an infinite number of objects, there are 2.5 ways to arrange them? Can you list them for us?

  • @matchedimpedance
    @matchedimpedance День тому

    Another shill video for Brilliant

  • @CindyBox-ro8wi
    @CindyBox-ro8wi День тому

    Blossom

  • @douglasstrother6584
    @douglasstrother6584 2 дні тому

    The Math Sorcerer would be proud.

  • @godzeira967
    @godzeira967 2 дні тому

    I didnt understand anything❤❤❤

  • @user-jl5xf1sx6g
    @user-jl5xf1sx6g 2 дні тому

    That makes perfect sense. I mean if I divide something by nothing, the proposition is un"defined" bc the result can be "ANYTHING" It holds infinite number of possibilities. How can one even "define" infinite possibilities tho. U cant pin point anything. Good one.

  • @ianbd77
    @ianbd77 2 дні тому

    I was expecting -1/12 for some reason

  • @eriliken7987
    @eriliken7987 2 дні тому

    Can please someone tell me why the limit of (1+1/x²)^x is 1?

  • @FirstLast-ml7yf
    @FirstLast-ml7yf 2 дні тому

    How can a divergent series be equal to anything?

    • @miloszforman6270
      @miloszforman6270 День тому

      You have to define it. There is no a priori meaning of expressions like 1+2+3+.... These notorious three dots "..." are frequently used in a "hand waving" kind of pseudo-mathematics, pretending that everyone would know what they mean. Now an expression like 1+2+3+...+28+29+30 is indeed relatively easy to understand, but it gets complicated if infinite sequences are involved. Usually some concept of "convergence" is used in these cases, but that is not necessarily so, apart from the fact that there are several concepts of convergence. Hardy and Ramanujan were discussing methods to assign some value to sequences like (1, 2, 3, ...) in a more or less "logical" or "useful" way, and they stated some requirements that such a "functional" should have. Especially, it was required to be identical to the traditional sum of convergent sequences. Question remains if we really should call that functional a "sum" if it is only remotely related to traditional sums.

  • @KasyapH
    @KasyapH 2 дні тому

    But using gamma function, I can't find factorial of 1/3

  • @johnlabonte-ch5ul
    @johnlabonte-ch5ul 2 дні тому

    Math, saying that ".99..." is 1, is like a builder constructing over the n'th floor decides he no longer needs the building beneath for support and goes freestyle.

    • @Chris-5318
      @Chris-5318 2 дні тому

      You saying that 0.999... isn't 1 is exactly like a clueless trolling muppet commenting. Are you ever going to try to prove your absurd claim that 0.999... isn't 1? Are you ver going to prove that 0.222... + 0.777... isn't 0.999...?

    • @thetaomegatheta
      @thetaomegatheta День тому

      You still haven't provided a single argument for decimals '0.999...' and '1' meaning different things, and you are yet to back your claim that 9 and 1 are not integers. As of right now, you have no case.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul День тому

      No proof necessary for this comment. Apparently you never read my other comments.

    • @thetaomegatheta
      @thetaomegatheta День тому

      'No proof necessary for this comment' Actually, yes, it is. 'Apparently you never read my other comments' I have dismantled them almost sentence-by-sentence. You are yet to actually prove that 1 and 9 are not integers, despite your claims.

    • @johnlabonte-ch5ul
      @johnlabonte-ch5ul День тому

      Actually, I have to thank you for responding to my comments. I have learned a lot by trying to verify what you say. I see no valid proof that ".99..." is 1. I still see infinity as incomplete, inconsistent and indefinite. The Archimedean property is interesting but see the problem as an artifact of the decimal number system. Not only must ".99..." not equal 1 but it also can't be "next to" 1. (There is no smallest number greater than 0, there is always a number smaller than epsilon. ie a number smaller than epsilon becomes a new epsilon. )

  • @user-ee9jj5kr9r
    @user-ee9jj5kr9r 2 дні тому

    ❤❤

  • @alejandroatoche858
    @alejandroatoche858 2 дні тому

    Proving this you used the chain rule which actually uses the derivatives as fractions too. You used the thing you are trying to prove as an esencial part of the proof. In the chain rule (du/dy)x(dy/dx), dy just cancels out like a fraction as well

  • @JoaoVitorBarg
    @JoaoVitorBarg 3 дні тому

    its parallel to both axis

  • @chuateambush2011
    @chuateambush2011 3 дні тому

    It's 1/e not e^-pi/2😂

  • @Aditya-005
    @Aditya-005 3 дні тому

    This will be always smaller than 1

  • @independentballerina
    @independentballerina 3 дні тому

    Allah razı olsun ❤🎉

  • @betaorionis2164
    @betaorionis2164 3 дні тому

    But, isn’t the chain rule a consequence of treating dy/dx as a fraction?

  • @enesbatuhan7833
    @enesbatuhan7833 3 дні тому

    this is a result of treating infinity as a regular number. S = infinity if, S = 1 + 9S 9S = nine times infinity = infinity 1 + infinity = infinity S = S special rules like this are the reason why zero and infinity are later additions to maths. they needed to figure out how to implement them without breaking the fundamentals of maths. it's not like the concept of nothing was unknown to mathematicians until someone discovered zero.

  • @pranavbatra2904
    @pranavbatra2904 3 дні тому

    Wow

  • @user-be1ii6rq8q
    @user-be1ii6rq8q 3 дні тому

    When i have 168 cards in UNO deck

  • @zonked1200
    @zonked1200 3 дні тому

    1-1 + 1-1 for infinity is 0 because 0+0+0 etc is 0. 2A = 0, because 2*0 is 0. 1-A=A is nonsense. That's saying 1-0=0.

  • @them_gamer8460
    @them_gamer8460 3 дні тому

    This only works when a = 1 (the quadratic equation has its coefficient of x^2 as 1)

  • @walterrutherford8321
    @walterrutherford8321 3 дні тому

    Look at the pattern of the running subtotals 1/2 3/4 7/8 … (2^n-1)/2^n = 1 - (1/(2^n)) a smaller and smaller fraction less than one.

  • @VinodKanwar-o3w
    @VinodKanwar-o3w 3 дні тому

    😢🎉

  • @VinodKanwar-o3w
    @VinodKanwar-o3w 3 дні тому

    While adding B to B why he shift one B to right

  • @luckyizzac
    @luckyizzac 3 дні тому

    One approaches infinity faster than the other

  • @uggupuggu
    @uggupuggu 3 дні тому

    soO On 😂😂

  • @hrsulabh
    @hrsulabh 3 дні тому

    Bro but why there exits an extragenous root Is there a domain for w(xe^x)=x As till second last step 3 satisfies but after introducing lambert function [ whose domain is -1/e to infinity which is satisfies] and using xe^x, 3 is not yet the soln As solving in elegant way always requires each step to be accurate

  • @Ste3lyDan
    @Ste3lyDan 3 дні тому

    Don't show this to your calculus teacher

  • @kavinesh_the_legend
    @kavinesh_the_legend 3 дні тому

    Teacher: There is nothing greater than infinite Vsauce: OR IS IT!!!

  • @BitolaMapping
    @BitolaMapping 3 дні тому

    i havent watched the video but it seems like the 0th root is impossible as the root0 of x can be rewritten as x^(1/0) and division by 0 isn't possible

  • @ernststravoblofeld
    @ernststravoblofeld 3 дні тому

    It's a fraction. There's a weird philosophical bullshit around this because of the whole division by zero thing, but if you treat it like a fraction, it works. If people could just be honest, calculus is based on the idea that sometimes you can divide by zero, as long as you don't look directly at the zero.